Biden to Host Zelensky , at White House Again.
President Joe Biden will welcome President Volodymyr Zelensky to Washington on Dec.
12 as Congress remains divided on additional aid for Ukraine, CNN reports.
.
President Joe Biden will welcome President Volodymyr Zelensky to Washington on Dec.
12 as Congress remains divided on additional aid for Ukraine, CNN reports.
.
This will be Zelensky's third White House visit since the war between Russian and Ukraine began.
The meeting is intended to "underscore the United States’ unshakeable commitment to supporting the people of Ukraine as they defend themselves against Russia’s brutal invasion," according to press secretary Karine Jean-Pierre.
The meeting is intended to "underscore the United States’ unshakeable commitment to supporting the people of Ukraine as they defend themselves against Russia’s brutal invasion," according to press secretary Karine Jean-Pierre.
As Russia ramps up its missile and drone strikes against Ukraine, the leaders will discuss Ukraine’s urgent needs and the vital importance of the United States’ continued support at this critical moment, Karine Jean-Pierre, White House press secretary, via statement.
Congressional negotiations to allow emergency aid to both Ukraine and Israel have been impeded by Senate Republicans' desire to include immigration and border policy changes to the deal.
Congressional negotiations to allow emergency aid to both Ukraine and Israel have been impeded by Senate Republicans' desire to include immigration and border policy changes to the deal.
Both sides are hoping to reach an agreement before lawmakers embark on their holiday break.
While Biden says he's willing to entertain "significant compromises on the border," .
He condemned "extreme Republicans" for "playing chicken with our national security.".
Sen.
J.D.
Vance of Ohio took to X to make his feelings known.
In the midst of a historic border crisis, Zelensky will come to Washington and demand that the Congress care more about his border than our own, Sen.
J.D.
Vance, via X
